椭圆x＾2/27＋y＾2/36＝1 是这个吗c^2=a^2-b^2=36-27=9c=3设双曲线为:y^2/a^2-x^2/b^2=1a^2+b^2=c^2=9与椭圆的交点横坐标的平方:x^2/27+16/36=1,x^2=1516/a^2-15/b^2=1所以a^2=4,b^2=5y^2/4-x^2/5=1...