解由函数f(x)=sin(x+π/3)-m/2在[0,π]上有两个零点即方程sin(x+π/3)-m/2=0在[0,π]上有两个根即方程m=2sin(x+π/3)在[0,π]上有两个根令y1=m,y2=2sin(x+π/3) x属于[0,π]则在同一坐标系下做出y1,y2的图像,则y1,y2...