已知sin(pai/4+2a)sin(pai/4-2a)=1/4,a属于(pai/4,pai/2),求2sin^a+tana-cota-1的值
需要全步骤,2sin平方a.
人气:269 ℃ 时间:2020-02-06 05:11:58
解答
sin(π/4+2a)sin(π/4-2a)=sin[π/2-(π/4-2a)]sin(π/4-2a)=cos(π/4-2a)sin(π/4-2a)=[cos(4a)]/2=1/4 ==>cos(4a)=1/2,因为a属于(π/4,π/2),所以4a属于(π,2π),所以4a=5π/3,所以a=5π/12所以2(sina)^2+ta...
推荐
- 帮下 已知sin(π/4+2a) * sin(π/4-2a) =1/4 ,a∈(π/4,π/2,求2sin^a+tana-cota-1的值.
- a属于(0,pai/2) tana=1/2 求tan2a和sin(2a+pai/3)的值
- sin^2a+sin2a.cosa-cos2a=1,求sina,tana的值 a∈(0,pai/2)
- 已知tana+cota=5/2,求cos2a和sin(2a+π/4)
- 已知sin(兀/4+2a)sin(兀/4-2a)=1/4,a(兀/4,兀/2),求2sin^a+tana-cota-1的值(详细)
- The gap's being closed easily enables people to enjoy...
- 英语:so far this year we () a fall in house prices by between 3 and 5 percent
- I hate those people who like to take sth out of nothing.
猜你喜欢