已知tana+cota=5/2,求cos2a和sin(2a+π/4)
如题
人气:330 ℃ 时间:2020-02-05 16:36:52
解答
tana+cota=sina/cosa+cosa/sina=[(sina)^2+(cosa)^2]/sinacosa=1/(1/2sin2a)=5/2
sin2a=4/5
cos2a=3/5或-3/5
sin(2a+π/4)=sin2acosπ/4+sinπ/4cos2a=7√2/10或√2/10
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