帮下已知sin(π/4+2a) * sin(π/4-2a) =1/4 ,a∈(π/4,π/2,求2sin^a+tana-cota_数学解答

帮下已知sin(π/4+2a) * sin(π/4-2a) =1/4 ,a∈(π/4,π/2,求2sin^a+tana-cota-1的值.
已知sin(π/4+2a) * sin(π/4-2a) =1/4 ,a∈(π/4,π/2,求2sin^a+tana-cota-1的值.
a∈(π/4,π/2)

人气：290 ℃　时间：2020-03-29 20:25:52

解答

sin(π/4+2a) * sin(π/4-2a) =1/4则(1/2)[cos4a-cos(π/2)]=1/4cos4a=1/2a∈(π/4,π/2)2a∈(π/2,π)可见cos2a0由cos4a=2cos²2a-1=1/2 cos²2a=3/4cos2a=-√3/2 (1)又cos4a=1-2sin²2a=1/2 sin²...