已知：x^2-5x-2002=0求:(x-2)^3/x-2-(x-1)^2+1=?:(x-2)^3/x-2-(x-1)^2+1=(x-2)^2-(x-1)^2+1=(x-1-1)^2-(x-1)^2+1=(x-1)^2-2(x-1)+1-(x-1)^2+1=4-2xx^2-5x-2002=0x不是整数解!看看有没有打错题....