因为X^2-5X-2007=0,即X^2-5X=2007
所以
[(X-2)^3-(X-1)^2+1]/(X-2)=(x-2)^2-(x^2-2x+1)/(x-2)+1/(x-2)
=(x-2)^2-(x^2-2x)/(x-2)-1/(x-2)+1/(x-2)
=x^2-4x+4-x- 1/(x-2)+1/(x-2)
=x^2-5x+4
=2007+4
=2011