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数学
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数列{an}中,a1=3,an-an+1=1(n∈N*),An表示数列{an}的前n项之积,则A2009=
人气:445 ℃ 时间:2020-09-28 15:30:33
解答
an-a(n+1)=1
a(n+1)-an=-1
{an}是等差数列,an=a1+(n-1)d=3-(n-1)=4-n
可得a4=0
故A2009=a1*a2*a3*a4.*a2009=0
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