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1/2log3(6)-log3(根号2);
log1/2(48)-log1/2(3);
lg25/12+lg 48
人气:257 ℃ 时间:2020-02-04 22:24:25
解答
1‘、原式=log3(√6)-log3(√2)
=log3(√6/√2)
=log3(√3)
=1/2..
2、原式=log1/2(48/3)
=log1/2(16)
=log1/2[(1/2)^(-4)]
=-4..
注:也可以套换底公式:
log1/2(16)=log2(16)/log2(1/2)
=4/(-1)
=-4.
3、原式=lg[(25/12)*48]
=lg100
=2..
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