若xy-x-y-4=0,求(xy-1)的平方-2x的平方y-2xy的平方+x的平方+y的平方+6xy-2x-2y的值.(要完整的过程)
人气:498 ℃ 时间:2020-04-03 11:36:18
解答
解析:若xy-x-y-4=0,那么:xy=x+y+4,xy-x-y=4(xy-1)²-2x²y-2xy²+x²+y²+6xy-2x-2y=(xy-1)²-2xy(x+y)+x²+2xy+y²+4xy-2x-2y=(xy-1)²-2xy(x+y)+(x+y)²+2(2xy-x-y)=(x...
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