（x^2-3x+2）^5=a0+a1x+a2x^2+……+a10x^10
=[(x²-3x)+2]^5
=2^5+5*2^4(x²-3x)+………………
=32+80(x²-3x)+…………
=32-240x+80x²+…………
a0=32 a1=-240
所以
a0+a1=-208