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证明函数f(x)=ax+b/x(a>0,b>0)在区间[根号b/a,+∞)上是增函数
人气:449 ℃ 时间:2019-08-19 11:26:32
解答
x1,x2∈[√b/a,+∞),x1<x2f(x1)-f(x2)=ax1+b/x1-ax2-b/x2=a(x1-x2)b(x2-x1)/x1x2=(x1-x2)(a-b/x1x2)=(x1-x2)(ax1x2-b)/x1`x2x1-x2<0x1,x2∈[√b/a,+∞)x1x2>b/aax1x2-b>0(x1-x2)(ax1x2-b)/x1`x2<0f(x1)-f(x2)...
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