设f(x)=
,又记f
1(x)=f(x),f
k+1(x)=f(f
k(x)),k=1,2,…则f
2011(x)=( )
A. -
B. x
C.
D.
人气:159 ℃ 时间:2019-09-18 02:38:37
解答
f1(x)=1+x1−x,f2(x)=f(f1(x))=-1x,f3(x)=f(f2(x))=1−1x1+1x=x−1x+1,f4(x)=f(f3(x))=1+x−1x+11−x−1x+1=x,f5(x)=f(f4(x))=1+x1−x∴函数解析式以4为周期,成周期出现∵f2011(x)...
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