f(X)=Inx-ax+（1-a）/x-1(a=R）定义域(0,+∞)f'(x)=1/x-a+(a-1)/x² =[-ax²+x+(a-1)]/x²=-(x-1)[ax+(a-1)]/x²当a=0时,f'(x)=(x-1)/x²≥0f(x)在(0,1)上为减函数,在(1,+∞)上为增函数当a≠0时...