∫(-1,1) x/√(5-4x)dx
Let z=5-4x => x=(5-z)/4 and dx=(-1/4)dz
When x=-1,z=9 // when x=1,z=1
So the integral = ∫(9,1) (5-z)/4 * 1/√z * (-1/4)dz
= (1/16)∫(1,9) (5-z)/√zdz
= (5/16)∫(1,9) 1/√zdz - (1/16)∫(1,9) √zdz
= (5/16)*2√z[1,9] - (1/16)*(2/3)*z^(3/2)[1,9]
= (5/8)(3-1) - (1/24)(27-1)
= 5/4 - 13/12
= 1/6