楼下的化简错了哦!f(X)=cos(√3x+φ)-√3sin(√3x+φ)=2[(1/2)cos(√3x+φ)-(√3/2)sin(√3x+φ)] tanπ/3=√3=2[cosπ/3cos(√3x+φ)-sinπ/3sin(√3x+φ)]=2cos(π/3+√3x+φ)因为f(x)是偶函数所以,f(x)=f(-X)所以...