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已知sin(x/2)=2cos(x/2),求(cos2x)÷[﹙√2﹚cos(45°+x)]sinx
人气:459 ℃ 时间:2020-03-24 05:55:28
解答
∵sin(x/2)=2cos(x/2)∴sin(x/2)/cos(x/2)=2cos(x/2)/sin(x/2)=1/2∴(cos2x)÷{[﹙√2﹚cos(45°+x)]sinx}=(cos²x-sin²x)÷{[√2(cos45ºcosx-sin45ºsinx)]sinx}=(cosx+sinx)(cosx-sin...
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