(1)由f(x)=sin(2x+φ)+acos(2x+φ)≤√1+a²则由√1+a²=2及a＞0,求得a=√3于是f(x)=sin(2x+φ)+ √3cos(2x+φ)=2〔sin(2x+φ)·cosπ/3+cos(2x+φ)·sinπ/3〕=2sin(2x+π/3+φ).又f(x)的图象关于直线x=π/...