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数学
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函数y=2sin(2x+π/4)的单调递增区间怎么求
人气:181 ℃ 时间:2020-02-27 21:14:55
解答
-π/2+2kπ≤2x+π/4≤π/2+2kπ
-3π/4≤2x≤π/4
-3π/8≤x≤π/8
单调区间为[-3π/8,π/8]
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