√[(x^2+2)/x]-√[x/(x^2+2)]=5设y=(x^2+2)/x,y>0原方程化为:√y-√(1/y)=5平方,得：y-2+1/y=25y+1/y-27=0y^2-27y+1=0y=(27±5√29)/21)y=(27+5√29)/2时(x^2+2)/x=(27+5√29)/22(x^2+2)=(27+5√29)x2x^2-(27+5√29)...