∵f(x)=2x^3-3x+1=2x^3-2x-x+1=2x(x^2-1)-(x-1)
=2x(x+1)(x-1)-(x-1)=(x-1)(2x(x+1)-1)
=(x-1)(2x^2+2x-1)
∴该函数有三个零点,分别是1,（-1±√3）/2.