3sin^2(α)+2sin^2(β)=2sinα则cos^2(α)+cos^2(β)的取值范围
人气:480 ℃ 时间:2020-04-08 21:14:35
解答
3sin^2(α)+2sin^2(β)=2sinαsin^2(α)+(2-2cos^2(α))+(2-2cos^2(β))=2sinαcos^2(α)+cos^2(β)=[sin^2(α)-2sinα+4]/2设sinα=t因为2sin^2(β)=2sinα-3sin^2(α)≥02t-3t^2≥02/3≥t≥0cos^2(α)+cos^2(β)=[...
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