分式题:xy=x+y,yz=2(y+z),zx=3(z+x),求xyz/(xy+yz+xz)
xy=x+y,yz=2(y+z),zx=3(z+x),求xyz/(xy+yz+xz)
人气:182 ℃ 时间:2019-08-21 21:03:45
解答
xy+yz+xz=1/2x(y+z)+1/2y(x+z)+1/2z(x+y)=(1/2x)*(1/2yz)+1/2y*(1/3zx)+1/2z*(xy)=11/12xyz
应该知道答案了吧
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