设f(x)=sin兀x（x=0),g(x)=cos兀x(x=1/2)求g(1/4)+f(1/3)+g(5/6)+f(3/4)的值_数学解答

设f(x)=sin兀x（x=0),g(x)=cos兀x(x=1/2)
求g(1/4)+f(1/3)+g(5/6)+f(3/4)的值

人气：398 ℃　时间：2020-06-12 06:00:54

解答

g(1/4)+f(1/3)+g(5/6)+f(3/4)
=cos(兀/4)+f(-2/3)+1+g(-1/6)+1+f(-1/4)+1
=√2/2-√3/2+1+√3/2+1-√2/2+1
=3.
谢谢!