m=2
n=3-根号7
mn=2(3-根号7)=6-2根号7
n^2=(3-根号7)^2=16-6根号7
1=amn+bn^2=a(6-2根号7)+b(16-6根号7)=6a+16b-(2a+6b)根号7
1=6a+16b-(2a+6b)根号7
左边是有理数,右边的根7的系数必为0,即：
2a+6b=o (1)
6a+16b=1 (2)
解出：a=3/2 b=-1/2
2a+b=2*3/2+(-1/2)=5/2