设函数f(x)=ax^2+bx+c,且f(1)=-a/2,3a>2c>b 求证1)a>0,-3
3a>2c>2b
人气：466 ℃ 时间：2020-05-07 19:14:41
解答
f(1)=-a/2=a+b+c
3a+2b+2c=0>b+2b+2b
b0
03a+2b+2b
b/a
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