分解下列因式:
(1)m2-n2+2m-2n
(2)1-x2-y2+2xy
(3)x2-(k+3)x+(k+2)
(4)(m2-1)(n2-1)+4mn.
人气:471 ℃ 时间:2020-04-11 22:36:26
解答
(1)m2-n2+2m-2n=(m+n)(m-n)+2(m-n)=(m+n)(m-n+2);(2)1-x2-y2+2xy=1-(x2+y2-2xy)=1-(x-y)2=(1+x-y)(1-x+y);(3)x2-(k+3)x+(k+2)=(x-2-k)(x-1);(4)(m2-1)(n2-1)+4mn=m2n2-n2-...
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