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数学
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计算1+3+5+7+...+2009+2011
人气:132 ℃ 时间:2020-04-04 11:12:45
解答
1+3==4=2^2(就是2的平方)
1+3+5==9=3^2
1+3+5+7=16=4^2
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1+3+5+7+...+2009+2011=[(1+2011)/2]^2=1006^2=100000036
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