已知三角形三边abc,m为正数,证明:[a/(a+m)]+[b/(b+m)]>[c/(c+m)] 谁能帮证明一下,
人气:182 ℃ 时间:2020-04-04 18:39:19
解答
因为a+b>c,所以a+b/a+b+m>c/c+m又(a/a+m)+(b/b+m)=(2ab+am+bm/ab+am+bm+m*m)>(am+bm/am+bm+m*m)=(a+b/a+b+m)
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