f(x)=√3sin2x+cos2x-1=2sin(2x+π/6)-1
(2x+π/6-n)=2x或2x+π/6-n=2x-π
π/6-n=0或π/6-n=-π
n=π/6或n=7π/6
g(x)=2sin2x-1或g(x)=2sin(2x-π)-1平移后函数g(x)=2sin(2x-2n+π/6)-1吧，还有就是为什么直接就(2x+π/6-n)=2x或2x+π/6-n=2x-π...我没看懂额...高手在指点指点吧-π/2<(2x-2n+π/6)<π/22x-2n+π/6=-π/2, π+π/6=2n n=7π/12 -2n+π/6=-π g(x)=2sin(2x-π)-12x-2n+π/6=π/2 π/6=2n n=π/12-2n+π/6=0 g(x)=2sin2x-1