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数列an中,a1=3 am+n=am.an 则sn/an的极限是多少
人气:133 ℃ 时间:2020-05-11 09:53:49
解答
a(m+n)=am.an
m=1
a(n+1)=a1.an
=3an
{an}是等比数列,q=3
an = 3^(n-1) .a1
= 3^n
Sn = (3/2)(3^n-1)
lim(n->∞)Sn/an
=lim(n->∞) (3/2)( 1- 1/3^n)
=3/2
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