y'=3x^2-10x+3=(3x-1)(x-3),得极值点x=1/3, 3y"=6x-10=2(3x-5), 得拐点x=5/3单调增区间：x3; 单调减区间：(1/3, 3)极大值f(1/3)=1/27-5/9+1-5=-122/27极小值f(3)=27-45+9-5=-14凸区间：x5/3, f(5/3)=125/27-125/9+5-...