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数学
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x-y/x-2y÷[x2-y2/x2-4xy+4xy2]其中x=1+√2,y=1-√2
人气:408 ℃ 时间:2020-10-02 02:07:33
解答
(x-y)/(x-2y)÷(x²-y²)/(x²-4xy+4y²)
=(x-y)/(x-2y)×(x-2y)²/(x+y)(x-y)
=(x-2y)/(x+y)
=[(3√2)-1]/2
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