y=log0.25x-log0.5x+2=log1/4(x)-log1/2(x)+2= -1/2log2(x)-log1/2(x)+2
=log2(x^1/2)+2
x^1/2>0
x>0
令t=x^1/2,y=log2(t)
t=x^1/2在(0,+无穷)上是增函数,y=log2(t)也是增函数,由复合函数关系得
函数函数y=log0.25x-log0.5x+2的单调增区间是(0,+无穷)
没有减区间啊?