| 8 |
| 5 |
=-9-8+2
=-15；
（2）原式=（-3）2004×（-
| 1 |
| 3 |
| 1 |
| 3 |
=[（-3）×（-
| 1 |
| 3 |
| 1 |
| 3 |
=12004×（-
| 1 |
| 3 |
=-
| 1 |
| 3 |
（3）设
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2005 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2004 |
则原式=a（1+b）-（1+a）•b
=a+ab-b-ab
=a-b
=
| 1 |
| 2005 |
| 8 |
| 5 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2005 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2004 |
| 1 |
| 2 |
| 1 |
| 2005 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2004 |
| 8 |
| 5 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2005 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2004 |
| 1 |
| 2005 |