> 数学 >
求x(cosx)方dx的积分
人气:451 ℃ 时间:2020-04-13 05:36:32
解答
∫xcos^2 x dx
=∫x(cos2x+1)/2 dx
=1/2*∫xcos2xdx+1/2*∫xdx
=1/4∫xcos2xd2x+1/4∫dx^2
=1/4∫xdsin2x +x^2/4
=1/4 *xsin2x-1/4∫sin2xdx +x^2/4
=xsin2x/4+x^2/4-1/8∫sin2xd2x
=xsin2x/4+x^2/4+1/8∫dcos2x
=xsin2x/4+x^2/4+cos2x/8 + C
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版