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求(2sin78°-sin18°)/(2cos78°+根号3sin18°)的值.
人气:409 ℃ 时间:2020-06-19 02:24:46
解答
(2sin78°-sin18°)/(2cos78°+根号3sin18°)
=(2sin(60°+18度)-sin18°)/[2cos(60°+18°)+根号3sin18°]
=(2sin60°cos18°+2cos60°sin18°-sin18°)/(2cos60°cos18°-2sin60°sin18°+根号3sin18°)
=(根号3cos18°+sin18°-sin18°)/(cos18°-根号3sin18°+根号3sin18°)
=根号3cos18°/cos18°
=根号3
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