正五边形ABCDE的对角线AC和BE相交于M,求证:(1)AC‖DE(2)ME=AE
人气：158 ℃ 时间：2020-05-22 04:57:01
解答
∵正五边形,∴AB=EA,∠EAB=108°,∴∠EBA=∠BEA=36°
∵AE=BC,AB=AB,∠EAB=∠CBA,∴△EAB≌△CBA,∴∠CAB=∠EBA=36°
∴∠EMA=∠EAB=72°,ME=AD=AB
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