1+1/2+1/3+1/4+1/5+.+1n 求 前n项和
人气：361 ℃ 时间：2020-04-29 01:40:28
解答
令 S(n) = 1+1/2+1/3+1/4+1/5+1/6+...1/n,则 S(∞) = 1 + (1/2+1/3) + (1/4+1/5+1/6+1/7) + ...< 1 + (1/2+1/2) + (1/4+1/4+1/4+1/4) + ...且 S(∞) = 1 + 1/2 +(1/3+1/4) + (1/5+1/6+1/7+1/8) + ...> 1 + 1/2 +(1/4...
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