(a+1)(a2+1)(a4+1)(a6+1)(a8+1)+1=
人气:310 ℃ 时间:2020-07-04 10:33:53
解答
(a+1)(a2+1)(a4+1)(a6+1)(a8+1)+1=[(a-1)(a+1)(a2+1)(a4+1)(a6+1)(a8+1)]/(a-1)+1=[(a2-1)(a2+1)(a4+1)(a6+1)(a8+1)]/(a-1)+1=[(a4-1)(a4+1)(a6+1)(a8+1)]/(a-1)+1=(a8-1))(a8+1))(a6+1)]/(a-1)+1==[(a16-1)(a6+1)]/...
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