lim(1+x^2-cos2x)^(1/lnx),x趋近于0+
人气:218 ℃ 时间:2020-07-06 10:49:36
解答
lim (1 + x^2-cos2x) ^ (1/lnx) (x—>0+)=lim [ x^2 + 2(sinx)^2 ] ^ (1/lnx) =lim [ x^2(1 + 2(sinx/x)^2) ] ^ (1/lnx) =lim (x^2)^(1/lnx) * lim [(1 + 2(sinx/x)^2) ]^(1/lnx)=lim (x^2)^(1/lnx) * 3^0 (x—...
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