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如图所示,已知圆O的弦AB垂直于直径CD,垂足为F,点E在AB上,且EA=EC.
证明:AC²=AE×AB
人气:491 ℃ 时间:2019-10-18 23:58:04
解答
已知,EA = EC ,可得:∠ACE = ∠CAE .CD是AB的垂直平分线,可得:AC = BC ,则有:∠BAC = ∠ABC .在△ACE和△ABC中,∠ACE = ∠CAE = ∠BAC = ∠ABC ,所以,△ACE ∽ △ABC ,可得:AC/AB = AE/AC ;即有:AC^2 = AE×AB...
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