数列{根号（ n+2）-2根号（n+1）+根号n},求前n项和的极限
人气：167 ℃ 时间：2019-11-04 03:28:48
解答
a(n) = [(n+2)^(1/2) - (n+1)^(1/2)] - [(n+1)^(1/2) - n^(1/2)],s(n) = a(1)+a(2)+...+a(n-1)+a(n)=[3^(1/2)-2^(1/2)]-[2^(1/2)-1^(1/2)] + [4^(1/2)-3^(1/2)]-[3^(1/2)-2^(1/2)] + ...+[(n+1)^(1/2)-n^(1/2)]-[n^(...
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