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∫[cos^2(x/2) +2sin^2 (x/2) ]dx
人气:369 ℃ 时间:2020-10-01 11:58:42
解答
∫ cos²(x/2) + 2sin²(x/2) dx
= ∫ cos²(x/2) + sin²(x/2) + sin²(x/2) dx
= ∫ dx + (1/2)∫ 2sin²(x/2) dx
= ∫ dx + (1/2)∫ (1 - cosx) dx
= (3x - sinx)/2 + C
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