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数学
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求cos1+cos2+cos3+…+cos178+cos179的值
人气:417 ℃ 时间:2020-02-02 06:14:18
解答
COSx+COS(180-x)=COSx-COSx=0
cos1+cos179=0
cos2+cos178 =0
…………
cos1+cos2+cos3+…+cos178+cos179
=(cos1+cos179)+(cos2+cos178)+(cos3+cos177)……
=0
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