a+b=(sina+1,√3+cosa)|a+b|²=(sina+1)²+(√3+cosa)²=sin²a+1+2sina+3+cos²a+2√3cosa=5+2sina+2√3cosa=5+4[sina*cos(π/3)+cosa*sin(π/3)]=5+4sin(a+π/3)因为正弦的最大值是1所以 |a+b...