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已知{log2an}为等比数列,且满足log2a1+log2a2+...log2a12=12,则a6*a7=
人气:285 ℃ 时间:2020-06-08 12:30:07
解答
log2a1+log2a2+...log2a12=12∴ log2 (a1*a2*.a12)=12,且a1,a2,.a12都是正数a1*a2*a3*.a12=2^12∵a1*a12=a2*a11=a3*a10=a4*a9=a5*a8=a6*a7∴ (a6*a7)^6=2^12∴ a6*a7=2^2=4
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