∵f（x）=√3*cos2x+2sinxcosx
=√3*cos2x+sin2x
=2(√3/2*cos2x+1/2*sin2x)
=2cos(2x-π/6)
又∵x∈[0,π/2]
∴2x-π/6∈[-π/6,5π/6]
∴f(x)∈[-√3,2]