解3x(x-1)=2-2x3x(x-1)-2(1-x)=03x(x-1)+2(x-1)=0(3x+2)(x-1)=0∴x=1或x=-2/32x+6=(x+3)²2(x+3)=(x+3)²(x+3)²-2(x+3)=0(x+3)(x+3-2)=0(x+3)(x+1)=0∴x=-1或x=-3