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设f(x)=sin(x/2)+cos(2x),f(π)的27阶导数
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人气:322 ℃ 时间:2019-09-20 00:10:02
解答
f(x)=(1/2^0)·sin(x/2) + (2^0)·cos(2x)f‘(x)=(1/2)·cos(x/2) + (-2)·sin(2x)=(1/2^1)·cos(x/2) + (-2^1)·sin(2x)f'‘(x)=[(-1/2^2)]·sin(x/2) + (-2^2)·cos(2x)f(x)的3阶导数=[(-1/2^3)]·cos(x/2) + (2^3...
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